5x^2-10+4x^2-3x+x=180

Solution for 5x^2-10+4x^2-3x+x=180 equation:

5x^2-10+4x^2-3x+x=180

We move all terms to the left:

5x^2-10+4x^2-3x+x-(180)=0

We add all the numbers together, and all the variables

9x^2-2x-190=0

a = 9; b = -2; c = -190;
Δ = b2-4ac
Δ = -22-4·9·(-190)
Δ = 6844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6844}=\sqrt{4*1711}=\sqrt{4}*\sqrt{1711}=2\sqrt{1711}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{1711}}{2*9}=\frac{2-2\sqrt{1711}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{1711}}{2*9}=\frac{2+2\sqrt{1711}}{18}
$